If you eat 1 pound of donuts that has 7000 calories, how much weight would you gain?
Would it be 1 pound or 2 pounds?
Immediately you would gain 1 pound, as if you were holding the donuts in your hand while standing on the scale. You’d just be holding them in your stomach.
After you digested them your weight gain, or maybe lack thereof, would be entirely dependent on your activity level around that time as well as how many calories you have already consumed or will consume in the near future.
Neither. Check out Jeff nippard a video on the 10k calorie science challenge. You will see increase in weight from water and glycogen yes, however you’re body will increase NEAT and thermogenesis. It will vary person to person
Someone can correct me if I’m wrong but 7000 calories is 1kg or 2.2lbs
So if your pound of donuts was in excess of your daily intake and there was nothing that reduced your total caloric intake you’d gain 1kg
Im assuming due to the fact is takes less energy to store the nutrient contents of donuts than say a chicken breast, then the donut would cause you to gain more weight. The exact math can be left up to someone smarter
Edit:I think I completely missed the assignment lol
You aren’t going to be able to find 1 pound of donuts with 7000 calories.
If you want calorie-dense, you need a lot of fat, lard is pretty dense at a little over 4000 calories per pound.
If you take an old-fashioned donut - one of the denser ones around - you only get 2100 calories per pound
The fact is that it couldn’t have 7000kcals in the first place, as that would exceed the caloric density of pure oil. Pure oil is roughly 4050 kcals per pound, and donuts are necessarily less calorie dense. So the example doesn’t work in real life anyway.
Your body doesn’t work like that. Metabolism isn’t a perfect calculator.
A person very well could eat over 7,000+ in a surplus one day and not gain anything.
Also technically the 3,500 calories in a pound thing is wrong.
Again that’s not how the body works. There are so many more factors at play.